calculus - Why $sum_{k=0}^infty (-1)^k frac{(ln 4)^k}{k!}=0.25$?

Hi can someone please explain why

$$\sum_{k=0}^{\infty} \frac{(-1)^k (\ln 4)^k}{k!} = 0.25$$

Your help is appreciated.

Answer

That expression is same as $e^{-ln(4)}$, and this is in fact $1/4$, i.e $0.25$